San Patricio Mathematics

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Saturday, November 27, 2010

Second Period Review Answer Key

1) CF = 74mm
DF = 62mm
m2) m3) m m m m4) Shaded area = 25π/4
m(arc) = 5π/6
5) Area de poligono = 108 cm2
Area del circulo = 25π cm2
Area sombreada = (108 - 25π) cm2
6) Area sombreada = 49π cm2
Area sin sombra = (196 - 49π) cm2
7) Area sombreada = 24π cm2
8) a) I y II (LAL)
b) I y III (ALA)
c) I, II, y III (LLL)
9) m m m m10) m m11) x = 8
y = 10 (pero esos triangulos rectas no son posibles)
12) BC = 27cm
13) a = 6
b = 18
c = 36√2
14) m
b = 2.5
15) a) = 100√145m
b) = distancia entre las ciudades A y C = 400(√13 + 2)m
(error donde se dice “entre las ciudades B y C”)
16) altura = 5.4m
17) razon de cambio = 2/5 (error en el ultimo dato – debe seria 30 y no 20)
18) entre los anos 1988-1990 y 1998-2000
Posted by joshua m. gerrard at 2:14 PM

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